225-16y^2=0

Solution for 225-16y^2=0 equation:

225-16y^2=0

a = -16; b = 0; c = +225;
Δ = b2-4ac
Δ = 02-4·(-16)·225
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-16}=\frac{-120}{-32}
=3+3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-16}=\frac{120}{-32}
=-3+3/4
$